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1.5-x^2/4.5=0
We multiply all the terms by the denominator
-x^2+(1.5)*4.5=0
We add all the numbers together, and all the variables
-1x^2+6.75=0
a = -1; b = 0; c = +6.75;
Δ = b2-4ac
Δ = 02-4·(-1)·6.75
Δ = 27
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{27}=\sqrt{9*3}=\sqrt{9}*\sqrt{3}=3\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-3\sqrt{3}}{2*-1}=\frac{0-3\sqrt{3}}{-2} =-\frac{3\sqrt{3}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+3\sqrt{3}}{2*-1}=\frac{0+3\sqrt{3}}{-2} =\frac{3\sqrt{3}}{-2} $
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